Abdullah Movahed Cup Freestyle Wrestling The winners of the first five weights were determined

According to Fars News Agency, the first international freestyle wrestling competition of Abdullah Movahed, winner of 6 Olympic and world gold medals, is being held in Amol city this morning, and tomorrow night it will be over with the announcement of the top individuals and teams.

The competitions of the first five weights of these competitions were held today, and the names of the top individuals are as follows:

45 kg: 1- Amir Mohammad Nawazi 2- Arman Haroutonian 3- Mohammad Amin Amani and Mohammad Reza Saghi 5- Ali Mohammad Rahmani 6- Reza Goran 7- Aristotle Junidi 8- Mohammad Sajjad Heidari

51 kg: 1- Mohammad Reza Asadi 2- Abolfazl Abdolvand 3- Hayko Gasparian (Armenia) and Hamid Reza Rezaei 5- Mohammad Safarpour and Ali Mohammad Taheri 7- Hossein Torabi 8- Ali Asghar Soltani 9- Abolfazl Razavi 10- Narik Hakobyan (Armenia)

60 kg: 1- Ebrahim Elahi Chorun 2- Sajjad Pirdayeh 3- Parsa Bahrami and Hadi Rezaei 5- Ali Asghar Tat and Abolfazl Zahedian 7- Saeed Parvaneh 8- Hamidreza Gohari 9- Mohammad Nikpour 10- Parham Inanloo

71 kg: 1- Mehdi Pak Nohad 2- Abolfazl Hosseini 3- Younes Shafiei and Abolfazl Kamervand 5- Abolfazl Rahmani 6- Seyed Hassan Moghimi 7- Farzin Yazdani 8- Amir Mehdi Moghadam 9- Abolfazl Bagheri 10- Mohammad Javad Taghavi

92 kg: 1- Erfan Alizadeh 2- Amirreza Daliri 3- Tohid Nouri and Abolfazl Maleki 5- Amir Hossein Khaki and Amir Bahador Khorami 7- Ashkan Bahadorfar 8- Navid Mohammadpour 9- Henrik Ikian (Armenia) 10- Mahan Salimi

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